Hi, Jonathan,
Ang Lee pointed out that the detector mass is not 200 ton, but quite a bit less.
I have calculated the mass for a 6.8 m diameter sphere , filled with mineral oil, made of 1/4 inch steel.
I get 147 (metric) ton total.
Supports and electronics may pop this up to about 150 ton, but not much more.
I think we need to be careful not to add safety factors at every stage.
Things can get funky quickly!
Hans
____________________________________________________________________________
By the way,
if the borehole cost dominates (as I suspect), it may be worth looking at slightly non-spherical shapes.
I have done a paper exercise of adding a cylindrical section equal to one radius (3.4 m) to the vessel.
As one might expect the mass goes up (from 147 ton to 256 ton),
accompanied by a large gain in fiducial volume, from 24.5 m^3 to 55 m^3, more than double.
It may be worth running the light collection Monte Carlo for this shape.
The gain ratio will be available at any diameter.
We may be able to do a better experiment, reduce cost, or both
Hans
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Pi
3.141593
diameter
6.8
m
Volume
164.6362
m^3
Density of oil
850
kg/m^3
Oil Mass
139940.8
kg
139.9408
ton
Surface area
145.2672
m^2
Steel thickness
6.35E-03
m
Steel density
7850
kg/m^3
Steel volume
9.22E-01
m^3
Steel mass
7.24E+03
kg
7.241209
ton
Fiducial volume diameter
3.5
m
Fiducial volume
22.4493
m^3
Total mass
1.47E+05
kg
147.182
ton
Add cylinder of height one radius:
Added height
3.4
m
Added volume
123.4772
m^3
Added mass
104955.6
kg
Added surface area
72.63362
m^2
Added steel volume
4.61E-01
m^3
Added steel mass
3.62E+03
kg
Total added mass
1.09E+05
kg
108.5762
ton
Fiducial volume diameter
3.5
m
Added Fiducial volume
32.71183
m^3
Total new mass
2.56E+05
kg
255.7582
ton
Total new fiducial volume
55.16113
m^3
Received on Wed Aug 4 08:49:12 2004
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